Reconstruction of the 2000 Wrotham formation |
|
1. |
 |
Start with constructing a equilateral triangle. |
|
2. |
 |
Draw three circles centered at each corner of the triangle
and tangent to the opposite sides. |
|
3. |
 |
Remove the parts of the circles, that lie outside the triangle. |
|
4. |
 |
Draw circles centered at the midpoint of each side of the triangle,
and tangent to the larger circles. |
|
5. |
 |
From the same midpoints, draw smaller circles,
touching the other two circles. |
|
6. |
 |
As with step 2, draw circles from each corner of the triangle,
that touch the latter smaller circles at the far side. |
|
7. |
 |
Again, remove from the last drawn circles all parts outside
the triangle. |
|
8. |
 |
Remove from all circles introduced in steps 4 and 5,
all parts inside the triangle; then, remove the triangle. |
|
9. |
 |
Finally, remove repeatedly two of the four cross-lines,
such that the woven-like knot pattern appears. |
|
10. |
 courtesy
The Crop Circle Connector
original image by:
Andrew King |
The final reconstruction fits neatly. |
|
|
I tried to find mathematical expressions with a graphical
representation similar to the pattern of the Wrotham formation.
I found the following quite complicated formulas.
|
|
xi =
r1
cos φi
|
(1) |
|
yi =
r1
sin φi | (2) |
|
ui = xi +
r2
cos –a·φi | (3) |
|
vi = yi +
r2
sin –a·φi | (4) |
|
pi = xi +
c·r2
cos –a·φi | (5) |
|
qi = yi +
c·r2
sin –a·φi | (6) |
|
With the following parameter setting:
|
|
a = 2
| |
|
b = 2.6
| |
|
c = 0.55
| |
|
r2 = b·r1
| |
|
φi = 0,...,2π
| |
the set of formula's will generate this pattern:
|
|
|
To understand what happens, look at the following pictures:
|
|
11. |
 |
Formula's (1) and (2) describe a point A
(xi,yi) "walking"
around a circle with radius r1.
Each position of point A is determined by the value of φ;
φ runs counter-clockwise. |
|
12. |
 |
Another circle with radius r2
(= 2.6 times r1)
has its center in point A. An other point B
(ui,vi) is walking
around this second circle, in the opposite direction,
and two times as fast (formula's (3) and (4)). |
|
13. |
 |
Following the path of point B results in the outer
loop of the Celtic knot pattern.
The last two formula's (5) and (6) generate the inner loop.
It is the path of a point C
(pi,qi),
that is just some distance (0.55 times r2)
from point A on the same ray as point B. |
|
|
|
Copyright © 2000, Zef Damen, The Netherlands Personal use only, commercial use prohibited.
|
 Since 1-February-2005
|
|